Shell脚本编程学习入门:Shell编程基础(1)(2)
二进制到十进制的转换
脚本 b2d 将二进制数 (比如 1101) 转换为相应的十进制数。这也是一个用expr命令进行数学运算的例子:
#!/bin/sh # vim: set sw=4 ts=4 et: help() { cat << HELP b2d -- convert binary to decimal USAGE: b2d [-h] binarynum OPTIONS: -h help text EXAMPLE: b2d 111010 will return 58 HELP exit 0 } error() { # print an error and exit echo "$1" exit 1 } lastchar() { # return the last character of a string in $rval if [ -z "$1" ]; then # empty string rval="" return fi # wc puts some space behind the output this is why we need sed: numofchar=`echo -n "$1" | sed 's/ //g' | wc -c ` # now cut out the last char rval=`echo -n "$1" | cut -b $numofchar` } chop() { # remove the last character in string and return it in $rval if [ -z "$1" ]; then # empty string rval="" return fi # wc puts some space behind the output this is why we need sed: numofchar=`echo -n "$1" | wc -c | sed 's/ //g' ` if [ "$numofchar" = "1" ]; then # only one char in string rval="" return fi numofcharminus1=`expr $numofchar "-" 1` # now cut all but the last char: rval=`echo -n "$1" | cut -b -$numofcharminus1` #原来的 rval=`echo -n "$1" | cut -b 0-${numofcharminus1}`运行时出错. #原因是cut从1开始计数,应该是cut -b 1-${numofcharminus1} } while [ -n "$1" ]; do case $1 in -h) help;shift 1;; # function help is called --) shift;break;; # end of options -*) error "error: no such option $1. -h for help";; *) break;; esac done # The main program sum=0 weight=1 # one arg must be given: [ -z "$1" ] && help binnum="$1" binnumorig="$1" while [ -n "$binnum" ]; do lastchar "$binnum" if [ "$rval" = "1" ]; then sum=`expr "$weight" "+" "$sum"` fi # remove the last position in $binnum chop "$binnum" binnum="$rval" weight=`expr "$weight" "*" 2` done echo "binary $binnumorig is decimal $sum" #
该shell脚本使用的算法是利用十进制和二进制数权值 (1,2,4,8,16,..),比如二进制"10"可以这样转换成十进制:
0 * 1 + 1 * 2 = 2
为了得到单个的二进制数我们是用了lastchar 函数。该函数使用wc –c计算字符个数,然后使用cut命令取出末尾一个字符。Chop函数的功能则是移除最后一个字符。
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