SQL Server 2005 ip地址点分十进制与长整形表示法相互转换
SQL Server 2005 ip地址点分十进制与长整形表示法相互转换
在SQL Server 2005 数据库设计时,为了查询效率,常常把点分十进制表示的ip地址设计为bigint类型。存储的时候,怎么把点分十进制转换为bigint,请参考下面的sql自定义函数:- USE [temp]
- GO
- /****** 对象: UserDefinedFunction [dbo].[UF_CovertIPToInt] 脚本日期: 08/06/2012 16:55:22 ******/
- SET ANSI_NULLS ON
- GO
- SET QUOTED_IDENTIFIER ON
- GO
- -- =============================================
- -- Author: ----
- -- Create date: 2009-05-11
- -- Description: 转换ip
- -- =============================================
- CREATE FUNCTION [dbo].[UF_CovertIPToInt]
- (
- @ip varchar(20)
- )
- RETURNS bigint
- AS
- BEGIN
- declare @pos int
- declare @sub1 varchar(10)
- declare @sub2 varchar(10)
- declare @sub3 varchar(10)
- declare @sub4 varchar(10)
- set @pos = charindex('.',@ip)
- if(@pos<1) return 0
- set @sub1 = substring(@ip,0,@pos)
- --select @sub1
- set @ip = substring(@ip, @pos+1 ,len(@ip) - @pos + 1)
- --select @ip
- set @pos = charindex('.',@ip)
- if(@pos<1) return 0
- set @sub2 = substring(@ip,0,@pos)
- --select @sub2
- set @ip = substring(@ip, @pos+1 ,len(@ip) - @pos + 1)
- --select @ip
- set @pos = charindex('.',@ip)
- if(@pos<1) return 0
- set @sub3 = substring(@ip,0,@pos)
- --select @sub3
- set @ip = substring(@ip, @pos+1 ,len(@ip) - @pos + 1)
- if(len(@ip)<1) return 0
- select @sub4 = @ip
- --select @sub4
- return cast(@sub1 as bigint ) * 16777216 + cast(@sub2 as bigint ) * 65536 + cast(@sub3 as bigint )*256 + cast(@sub4 as bigint )
- END
- select dbo.UF_CovertIPToInt('192.168.1.100') as ip
显示的时候,为了方便阅读,常常需要把bigint转换为点分十进制,请参考下面的自定义函数:
- USE [temp]
- GO
- SET ANSI_NULLS ON
- GO
- SET QUOTED_IDENTIFIER ON
- GO
- CREATE FUNCTION [dbo].[UF_ConvertIPToStr]
- (
- @ip bigint
- )
- RETURNS varchar(20)
- AS
- BEGIN
- RETURN cast((@ip/16777216)% 256 as varchar(4)) + '.' + cast( (@ip/65536)% 256 as varchar(4)) +'.'+ cast( (@ip/256)%256 as varchar(4))+ '.'+ cast( (@ip%256)as varchar(4))
- END
- select dbo.UF_ConvertIPToStr (3232235790) as ip
- select inet_aton('192.168.1.12');
- select inet_ntoa(3232235788);
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